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Selasa, 23 April 2013
Rabu, 17 April 2013
Pembahasan Soal Sphere Online Judge problem No.11
Hallo para sobat blogger, khususnya para programmer pemula.
Kali ini saya akan membahas soal pemrograman dari situs web Sphere Online Judge problem nomor 11.
Silahkan diterjemahkan sendiri soalnya ini.
ACM technicians faced a very interesting problem recently. Given a set of BTSes to visit, they needed to find the shortest path to visit all of the given points and return back to the central company building. Programmers have spent several months studying this problem but with no results. They were unable to find the
Sabtu, 05 Januari 2013
BAB 1D : Fungsi dan Prosedur - Procedure
Solusi BAB 1D : Fungsi dan Prosedur - Procedure
PROGRAM prosedur;var bil : integer;procedure TulisJawaban(x: integer);begin case x of 1..9: begin writeln('satuan'); end; 10..99: begin writeln('puluhan'); end; 100..999: begin writeln('ratusan'); end; 1000..9999: begin writeln('ribuan'); end; 10000..30000: begin writeln('puluhribuan'); end; end;end;beginwhile not eof(input) dobegin readln(bil); TulisJawaban(bil);end;end.BAB 1D : Fungsi dan Prosedur - Function
Solusi BAB 1D : Fungsi dan Prosedur - Function
PROGRAM fungsi;var bil: integer;function Faktorial(n: integer): longint;begin if (n = 0) then Faktorial := 1 else Faktorial := n * Faktorial (n - 1);end;function Valid(n: integer): boolean;begin Valid := (n >= 0) and (n <= 10);end;begin readln(bil); if (Valid(bil)) then writeln(Faktorial(bil)) else writeln('ditolak');end.BAB 1D : Fungsi dan Prosedur - Var Parameter
Solusi BAB 1D : Fungsi dan Prosedur - Var Parameter
PROGRAM varparameter;var a, b: integer;procedure Swap(var a, b: integer);var temp: integer;begin temp := a; a := b; b := temp;end;begin readln(a, b); Swap(a, b); writeln(a, ' ', b);end.BAB 1C : Perulangan - Bilangan Agak Prima
Solusi BAB 1C : Perulangan - Bilangan Agak Prima
PROGRAM agakprima;var pr,bts,tes,cek : longint; c,a : byte;begin readln(c); for a:=1 to c do begin readln(pr); cek:=0; tes:=3; bts:=trunc(pr/2); if ((pr mod 2=0) and (pr<>2)) or (pr=1) then inc(cek); while tes<=bts do begin if (pr mod tes=0) then begin inc(cek); if cek>2 then break; end; inc(tes); end; if cek>2 then writeln('TIDAK') else writeln('YA'); end;end.BAB 1C : Perulangan - Faktor Bilangan
Solusi BAB 1C : Perulangan - Faktor Bilangan
PROGRAM faktorbilangan;var N,i:longint;beginreadln(N);for i:=1 to N do begin if N mod i=0 then begin writeln(N/i:0:0); end;end;readln end.
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